SOLUTION: How many liters of a 65% acid solution must be added to 12 liters of a 20% acid solution to produce a 38% acid solution?
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Question 783513: How many liters of a 65% acid solution must be added to 12 liters of a 20% acid solution to produce a 38% acid solution?
Answer by edjones(8007) (Show Source): You can put this solution on YOUR website!
Let x be the liters of a 65% acid solution that must be added to 12 liters of a 20% acid solution to produce a 38% acid solution.
.65x + 20*12 = .38(x+12)
.65x+2.4=.38x+4.56
.27x=2.16
x=8 L
.
Ed
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