SOLUTION: how many liters of a 10% alcohol solution must be mixed with how many liters of a 50% solution to get 20 liters of a 40% solution?
Algebra.Com
Question 783105: how many liters of a 10% alcohol solution must be mixed with how many liters of a 50% solution to get 20 liters of a 40% solution?
Answer by mananth(16946) (Show Source): You can put this solution on YOUR website!
percent ---------------- quantity
Alcohol type I 10.00% ---------------- x liters
Alcohol type II 50.00% ------ 20 - x liters
Mixture 40.00% ---------------- 20
Total 20 liters
10.00% x + 50.00% ( 20 - x ) = 40.00% * 20
10 x + 50 ( 20 - x ) = 800
10 x + 1000 - 50 x = 800
10 x - 50 x = 800 - -1000
-40 x = -200
/ -40
x = 5 liters 10.00% Alcohol type I
15 liters 50.00% Alcohol type II
m.ananth@hotmail.ca
RELATED QUESTIONS
How many liters of a 10% alcohol solution must be mixed with 20 liters of a 40% solution... (answered by ewatrrr)
how many liters of a 10% alcohol solution must be mixed with 40 liters of a 50% sotion to (answered by scott8148)
how many liters of a 10% alcohol solution must be mixed with 60 liters of a 50% solution... (answered by Fombitz)
how many liters of a 10% alcohol solution must be mixed with 90 liters of a 50% solution... (answered by Fombitz)
How many liters of a 10% alcohol solution must be mixed with 50 liters of a 80% solution
(answered by Fombitz,modi.kk91)
How many liters of a 14 percent Alcohol Solution must be mixed with 20 liters of a 50... (answered by ewatrrr)
How many liters of a 10% alcohol solution must be mixed with 30 liters of a 50% solutionn (answered by jorel1380)
how many liters of a 10% alcohol solution must be mixed with 20 L of a 50% solution to... (answered by Alan3354)
How many Liters of a 50% alcohol solution must be mixed with 40 Liters to obtain a 60... (answered by ptaylor)