SOLUTION: I have to use elimination or substitution to solve this. I am able to do that if I can get it into two linear equations in two variables. The problem is: A chemist has 15% and 4

Question 782462: I have to use elimination or substitution to solve this. I am able to do that if I can get it into two linear equations in two variables.
The problem is: A chemist has 15% and 40% solutions of acid available. How may liters of each solution should be mixed to obtain 5 liters of a 20% acid solution?
Answer by josgarithmetic(39618) (Show Source): You can put this solution on YOUR website!
You need two variables.
x = amount of 15% acid
y = amount of 40% acid

One equation accounts for the concentrations of acid:

The other equation accounts for the quantities of the acid solutions:

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