SOLUTION: how many liters of 35% alcohol and 60% alcohol must be mixed together to make 40 liters of a solution that is 53% alcohol?
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Question 782217: how many liters of 35% alcohol and 60% alcohol must be mixed together to make 40 liters of a solution that is 53% alcohol?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how many liters of 35% alcohol and 60% alcohol must be mixed together to make 40 liters of a solution that is 53% alcohol?
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Equaton::
alch + alch = alch
0.35x + 0.60(40-x) = 0.52(40)
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Multiply thru by 100 to get:
35x + 60*40 - 0.60x = 52*40
-25x = -8*40
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x = (8/5)8
x = 64/5 = 12 4/5 liters (amt of 35% solution needed)
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Cheers,
Stan H.
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