SOLUTION: an automobile radiator holds 15 liters of fluid. There is currently a mixture in the radiator that is 70% antifreeze and %30 water. How much of this mixture should be drained and r

Question 779818: an automobile radiator holds 15 liters of fluid. There is currently a mixture in the radiator that is 70% antifreeze and %30 water. How much of this mixture should be drained and replaced by pure antifreeze so that the resulting mixture is %80 antifreeze?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
an automobile radiator holds 15 liters of fluid. There is currently a mixture in the radiator that is 70% antifreeze and %30 water. How much of this mixture should be drained and replaced by pure antifreeze so that the resulting mixture is %80 antifreeze?
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x=amount of current mixture to be drained and replaced by pure antifreeze.
70%(15-x)+100%x=80%(15)
10.5-0.7x+x=12
0.3x=1.5
x=5
amount of current mixture to be drained and replaced by pure antifreeze: 5 liters
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