SOLUTION: What quantity of pure acid must be added to 600 mL of a 50% acid solution to produce a 75% acid solution?

Question 778238: What quantity of pure acid must be added to 600 mL of a 50% acid solution to produce a 75% acid solution?
Found 2 solutions by FrankM, josgarithmetic:
Answer by FrankM(1040) (Show Source): You can put this solution on YOUR website!
You have 300ml acid, 300ml water. You want 75% acid, or 25% water.
300ml (water) = 25%
900ml (acid) = 75%
You must add another 600 ml acid
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Give a variable to how much pure acid.
Let y = volume in mL of pure acid to add.

Note that amount of acid in mixture or resulting solution will be and volume of resulting solution will be mL. We must assume you mean your concentration as volume/volume; otherwise, you will need the densities of your pure acid and of the 50% solution.

In your simplified description, your equation is ;

mL of the pure acid.
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