SOLUTION: How many liters of a 50% alcohol solution must be mixed with 80 liters if a 90% solution to get a 70% solution ?
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Question 776169: How many liters of a 50% alcohol solution must be mixed with 80 liters if a 90% solution to get a 70% solution ?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How many liters of a 50% alcohol solution must be mixed with 80 liters if a 90% solution to get a 70% solution ?
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Equation:
alc. + alc. = alc
0.50x + 0.90*80 = 0.70(x+80)
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50x + 90*80 = 70x + 70*80
20x = 20*80
x = 80 liters (amt. of 50% solution to add)
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Cheers,
Stan H.
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