SOLUTION: A liter of vinegar is 5% acid. How many more liters of pure acid are needed to get a mixture that is 81% acid?

Question 773669: A liter of vinegar is 5% acid. How many more liters of pure acid are needed to get a mixture that is 81% acid?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Data To Know First:
5% Vinegar is as weight/weight. Density 1.00 gram/ml.
Pure 100% Acetic Acid, assumed weight/weight, Density 1.049 gram/cm^3

Use mass to do the main solving.
Letting a = grams of acetic acid (100% acid),
the mass of acid in the 1 liter of 5% is -------

grams, where "g" was an abbreviation for "grams"

Equation first all in mass is then:

Note that the 1.00 in the rational equation stands for "100%" for "a".

The algebraic steps, not shown here, will lead to .....
grams
from which you must use density to find the result in volume liters:
Liters
The units conversion here is
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