A salesperson purchased an automobile that was advertised as averaging 27 mi/gal in the city and 38 mi/gal on the highway. A recent sales trip that covered 1706 miles required 53 gallons of gasoline. Assuming that the advertised mileage estimates were correct, how many miles were driven in the city?

Ans:

Let x miles be driven in the city.

Then miles driven in highway = 1706 - x

Gasolene required for city driving = x/27

Gasolene required for highway = (1706 - x)/38

Total gasoline = 

Multiplying by LCM of 27 and 38 which is 1026, to eliminate the denominator



Simplifying and grouping like terms







So miles driven in city = 756

Miles driven in highway = 1706 - 756 = 950



Hope you got it :) 

RELATED QUESTIONS

A salesperson purchased an automobile that was advertised as averaging 27 mi/gal in the... (answered by josgarithmetic)

A salesperson purchased an automobile that was advertised as averaging 27 mi/gal in the... (answered by josgarithmetic,richwmiller,MathTherapy)

A salesperson purchased an automobile that was advertised as averaging 27mi/gal in the... (answered by josgarithmetic)

A salesperson purchased an automobile that was advertised as averaging 25 mi/gal in the... (answered by vleith)

A salesperson purchased an automobile that was advertised as averaging 25 mi/gal in the... (answered by haileytucki)

A salesperson purchased a car that was advertised as averaging 25 mi/gal in the city and... (answered by ewatrrr)

A sales person purchased an automobile that was advertised as averaging 25mi/gal in the... (answered by stanbon)

a car used 14 gal. of gas an traveled a total distance of 550 mi. the car's fuel... (answered by stanbon)

a salesperson purchased a car that avg 25mpg in the city and 40 mpg on highway.  A recent  (answered by jrfrunner)