It is desired to draw off a part of 10 gallons of 30% solution of alcohol and to replace it by pure alcohol so as to produce a 50% solution. How many gallons should be drawn off?



Let us assume x gallons is drawn off and replaced with x gal of pure alcohol.



After drawing of x gallons of the 30% mix, what is left is (10 - x) gallons of 

30% mix.



Since it is a 30% mix, volume of alcohol in it = (10 - x)*30% = (10 - x)*0.3

= 3 - 0.3*x



After adding x gallons of pure alcohol, the total volume of the mix is again

back to 10 gallons.



In this new mix, the volume of alcohol is = original alcohol + x gallons =

(3 - 0.3*x) + x = 3 + 0.7*x



Now, this is given to be a 50% mix. i.e. ratio of alcohol in the mix is 0.5



Therefore, 









 gallons



Hope you got it :)





 

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