SOLUTION: A solution of 69% fertilizer is mixed with a solution of 20% fertilizer to form 490 liters of a 46% solution. How many liters of the 69% solution must be used?

Question 762586: A solution of 69% fertilizer is mixed with a solution of 20% fertilizer to form 490 liters of a 46% solution. How many liters of the 69% solution must be used?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
A solution of H% fertilizer is mixed with a solution of L% fertilizer to form M liters of a T% solution. How many liters of the H% solution must be used?

Let v = the amount of liters of the H% fertilizer. Unknown variable.
Let u = the amount of liters of the L% fertilizer. Unknown variable.

and
Solve for v in terms of u.
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