SOLUTION: How many pounds of chamomile tea that costs $18.20 per pound must be mixed with
12 lb of orange tea that costs $12.25 per pound to make a mixture that costs $14.63 per pound?
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Question 760705: How many pounds of chamomile tea that costs $18.20 per pound must be mixed with
12 lb of orange tea that costs $12.25 per pound to make a mixture that costs $14.63 per pound?
Answer by 2897696(96) (Show Source): You can put this solution on YOUR website!
I would solve this problem using a chart:
Type : P (money or percentage of item):A (amount of item): Total
C)chamomile tea:$18.20 <==multiply==> :x gets==> :18.20x
o)orange tea :$12.25 <==multiply==> :12 gets==> :147.00
m)mixture :$14.63 <==multiply==> :x+12 gets==> :14.63x+175.56
Now using the information on the chart, we can make an equation. Since it is a mixture, we add both teas to make this mixture so the equation is the total of c tea and o tea=mixture of tea. Which in math is:18.20x+147.00=14.63x+175.56
From here you simplify the equation and solve for x.
:)See if you can solve it from here, good luck!!;)
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