SOLUTION: how many liters of a 10 alcohol solution must be mixed with 12 liters of a 20% alcohol solution to get 14% solution
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Question 758408: how many liters of a 10 alcohol solution must be mixed with 12 liters of a 20% alcohol solution to get 14% solution
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how many liters of a 10% alcohol solution must be mixed with 12 liters of a 20% alcohol solution to get 14% solution
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Equation:
alch + alch = alch
0.10x + 0.20*12 = 0.14(x+12)
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10x + 20*12 = 14x + 14*12
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-4x = -6*12
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x = 18 liters (amt. of 10% solution needed)
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Cheers,
Stan H.
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