SOLUTION: The vat contained 40 liters of a 5 percent salt solution. How much of a 20 percent salt solution should be added to get a 10 percent salt solution?

Question 75758This question is from textbook Algebra 2: An Incremental Development
: The vat contained 40 liters of a 5 percent salt solution. How much of a 20 percent salt solution should be added to get a 10 percent salt solution? This question is from textbook Algebra 2: An Incremental Development

Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
The vat contained 40 liters of a 5 percent salt solution. How much of a 20 percent salt solution should be added to get a 10 percent salt solution?
:
Let x = amt of 20% solution required
:
We know then, that (x+40) will be the final amt.
:
A simple equation, (decimals representing the per cent)
.05(40) + .20x = .10(x+40)
:
2 + .2x = .1x + 4
:
.2x - .1x = 4 - 2
:
.1x = 2
x = 2/.1
x = 20 liters of the 20% salt required
:
Check: .05(40) + .2(20) = .1(20 + 40)
2 + 4 = .1(60)
:
How about this? Did it make sense to you? Any questions?
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