SOLUTION: A chemist needs 70 milliliters of a 24% solution but has only 18% and 39% solutions available. How many milliliters of each should be mixed to get the desired solution?
Algebra.Com
Question 751590: A chemist needs 70 milliliters of a 24% solution but has only 18% and 39% solutions available. How many milliliters of each should be mixed to get the desired solution?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
L=18%
H=39%
T=24%
M=70 milliliters
u= unknown volume for the 18%
v= unknown volume for the 39%
and
Solve the system for u and v and then apply the known values to compute u and v.
RELATED QUESTIONS
A chemist needs 130 milliliters of a 39% solution but has only 3% and 55% solutions... (answered by mananth)
A chemist needs 180 milliliters of a 39% solution but has only 15% and 69% solutions... (answered by TimothyLamb)
A chemist needs 150 milliliters of a 44% solution but has only 24% and 99% solutions... (answered by ankor@dixie-net.com)
A Chemist needs 170 milliliters of a 36% solution but has only 24% and 58% solutions... (answered by greenestamps,ikleyn,josgarithmetic)
A chemist needs 90 milliliters of a 20% solution but only has only 4% and 40% solutions... (answered by richwmiller)
a chemist needs 120 milliliters of a 30% solution but only has only 14% and 38% solutions (answered by josmiceli)
a chemist needs 110 milliliters of an 80% solution but has only 76% and 98% solutions... (answered by addingup)
A chemist needs 150 milliliters of a 65% solution but has only 32% and 77% solutions... (answered by stanbon)