SOLUTION: Science and medicine. A pharmacist wishes to prepare 150 mL of a 20% alcohol
solution. She has a 30% solution and a 15% solution in her stock. How much of each should be used in f
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Question 74968: Science and medicine. A pharmacist wishes to prepare 150 mL of a 20% alcohol
solution. She has a 30% solution and a 15% solution in her stock. How much of each should be used in forming the desired mixture?
Answer by psbhowmick(878) (Show Source): You can put this solution on YOUR website!
Let us suppose that 'x' ml of 30% alcohol be mixed with 'y' ml of 15% alcohol to form 150 ml of 20% alcohol.
150 ml of 20% alcohol consists = 30 ml of alcohol and (150 - 30) = 120 ml of water.
Similarly, 'x' ml of 30% alcohol contains = 0.3x ml and (x - 0.3x) = 0.7x ml of water.
Also, 'y' ml of 30% alcohol contains = 0.15y ml and (y - 0.15y) = 0.85y ml of water.
Thus total volume of alcohol in final mixture = (0.3x + 0.15y) ml and total volume of water in final mixture = (0.7x + 0.85y) ml.
But final mixture contains 30 ml alcohol and 120 ml water.
So, ______________(1)
and ______________(2)
Multiplying (1) by 7 and (2) by 3 and subtracting (1) from (2)
So, [from (1)]
Hence, 50 ml of 30% alcohol should be mixed with 100 ml of 15% alcohol.
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