SOLUTION: A pharmacist has 6L of a mixture that is 20% alcohol. How much pure alcohol must be added to obtain a mixture that is 70% alcohol?
Algebra.Com
Question 744729: A pharmacist has 6L of a mixture that is 20% alcohol. How much pure alcohol must be added to obtain a mixture that is 70% alcohol?
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
A pharmacist has 6L of a mixture that is 20% alcohol.
How much pure alcohol must be added to obtain a mixture that is 70% alcohol?
:
let x = amt of pure alcohol required
then
(6-x) = amt of 20% alcohol required
:
.20(6-x) + x = .70(6)
1.2 - .2x + x = 4.2
.8x = 4.2 - 1.2
.8x = 3
x = 3/.8
x = 3.75 L of pure alcohol required
:
:
Check: .2(2.25) + 3.75 = .7(6)
.45 + 3.75 = 4.2
RELATED QUESTIONS
To make a mixture that is not less than 95% alcohol, how much pure alcohol must be added... (answered by richwmiller)
Alcohol Mixture. How may gallons of pure alcohol should be mixed with 20 gal of a 15%... (answered by josgarithmetic)
There are 90 ml of pure alcohol in a bottle of 750 ml of water and alcohol mixture .Find... (answered by jorel1380)
what is the minimum amount of pure alcohol that must be added to a 24 liters of a 20... (answered by vleith)
how many liters of pure alcohol must be added to 15 liters of 20% solution to obtain a... (answered by Maths68)
How many liters of pure alcohol must be added to 15 liters of 20% solution to obtain a... (answered by ikleyn)
How much pure alcohol must be added to 40 oz of a 25%
solution to produce a mixture... (answered by stanbon,checkley71)
How many gallons of pure alcohol should be mixed with 20 gal of a 15% alcohol solution to (answered by wgunther)
how many gallons of pure alcohol should be mixed with 20 gal of a 15% alcohol solution to (answered by nyc_function)