SOLUTION: how many liters of pure alcohol must be mixed with 40 liters of a 25% alcohol solution to get 50% mixture

Algebra.Com
Question 738820: how many liters of pure alcohol must be mixed with 40 liters of a 25% alcohol solution to get 50% mixture
Answer by richwmiller(17219)   (Show Source): You can put this solution on YOUR website!
40*.25+x=.5(40+x)
x=20 liters

RELATED QUESTIONS

how many liters of pure alcohol must be mixed with 20 liters of 25% alcohol solution to... (answered by stanbon,oberobic)
How many liters of pure alcohol must be mixed with five liters of 20% concentration of... (answered by josgarithmetic)
how many liters of a 10% alcohol solution must be mixed with how many liters of a 50%... (answered by mananth)
how many liters of 25% alcohol must be mixed with 40 liters of a 35% alcohol solution to... (answered by Fombitz)
how many liters of 25% alcohol must be mixed with 40 liters of a 35 % alcohol... (answered by Fombitz)
How many Liters of a 50% alcohol solution must be mixed with 40 Liters to obtain a 60... (answered by ptaylor)
how many liters of a 10% alcohol solution must be mixed with 40 liters of a 50% sotion to (answered by scott8148)
[ how many liters of a 40% alcohol solution must be mixed with 60 liters of a 70%... (answered by TimothyLamb)
How many liters of a 10% alcohol solution must be mixed with 30 liters of a 50% solutionn (answered by jorel1380)