SOLUTION: A mixture of dried fruit and nuts sells for $4.30 per pound. Separately, the dried fruit sells for $2.50 per pound, and the nuts sell for $7.00 per pound. How much of each is neede

Question 732388: A mixture of dried fruit and nuts sells for $4.30 per pound. Separately, the dried fruit sells for $2.50 per pound, and the nuts sell for $7.00 per pound. How much of each is needed to make 50 pounds of the mixture?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
This problem fits a very general two-part mixture situation. Here will be the beginning of a purely symbolic solution.

L = $2.50/pound for the fruit
H = $7.00/pound for the nuts
T = $4.30/pound for the mixture
M = 50 pounds, quantity of the mixture
u = unknown pounds of fruit
v = unknown pounds of nuts

Objective is to solve for u and v. A system of equations is necessary.

and
More than one way to start this solution process from here, but you could begin by doing a few operations on the T equation. It may be transformed to a linear equation of the two variables in standard for or general form, whichever you wish. Anyhow, you have two linear equations in two unknowns. Solve!

Once solved for u and v, just substitute your given values to compute u and v.
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