SOLUTION: A chemist needs to produce a 60% acid mixture. She has 25% strength solution and 80% strength solution on hand. Rounding to the nearest thousandth (3 decimal places; nearest mL)

Question 727123:
A chemist needs to produce a 60% acid mixture. She has 25% strength solution and 80% strength solution on hand.
Rounding to the nearest thousandth (3 decimal places; nearest mL), how many liters of 80% solution does she add to create 1 liter of the 60% strength mixture?

Found 2 solutions by stanbon, checkley79:
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A chemist needs to produce a 60% acid mixture. She has 25% strength solution and 80% strength solution on hand.
Rounding to the nearest thousandth (3 decimal places; nearest mL), how many liters of 80% solution does she add to create 1 liter of the 60% strength mixture?
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Equation:
acid + acid = acid
0.25x + 0.80(1-x) = 0.60*1
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25x + 80 - 80x = 60
-55x = -20
x = 4/11 liter (amt. of 25% solution needed)
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1-4/11 = 7/11 liter (amt of 80% solution needed)
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Cheers,
Stan H.
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Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
.80x+.25(1-x)=.60*1
.80x+.25-.25x=.60
.55x=.60-.25
.55x=.35
x=.35/.55
x=.636 liters of 80% solution is used.
1-.636=.364 liters of 25% solution is used.
Proof:
.80*.636+.25*.364=.60
.51+.09=.60
.60=.60
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