SOLUTION: A 50% solution is added to a pure solution to get 40g of 60% solution/ How much pure solution is used.
Algebra.Com
Question 719832: A 50% solution is added to a pure solution to get 40g of 60% solution/ How much pure solution is used.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A 50% solution is added to a pure solution to get 40g of 60% solution/ How much pure solution is used.
------
Equation:
active + active = active
1*x + 0.50(40-x) = 0.60*40
--------------------
100x + 50*40-50x = 60*40
50x = 10*40
x = 8g (amt. of pure solution needed)
===============================
Cheers,
Stan H.
RELATED QUESTIONS
how many grams of pure salt must be added to 40g of a 20% salt solution to make a... (answered by stanbon,mananth)
How much pure alcohol must be added to 2 liters of a 30% solution to get a 50% alcohol... (answered by richwmiller)
How much pure antifreeze must be added to 12 L of a 40% solution to obtain a 60%... (answered by josmiceli)
A 60 mililiter solution has 50% acid. How much pure water is needed to get 30%... (answered by checkley71)
How much water should be added to 1 gallon of pure antifreeze to obtain a solution that... (answered by rapaljer)
How much water should be added to 1 gallon of pure antifreeze to obtain a solution that... (answered by stanbon)
How much water should be added to 1 gallon of pure antifreeze to obtain a solution that... (answered by ankor@dixie-net.com)
How much water should be added to 1 gallon of pure antifreeze to obtain a solution that... (answered by Alan3354)
How much water should be added to 4 liters of (pure) antifreeze to make a solution that... (answered by robertb)