SOLUTION: How many liters of a 30% alcohol solution must be mixed with 60 liters of 90% solution to get a 60% solution?
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Question 718229: How many liters of a 30% alcohol solution must be mixed with 60 liters of 90% solution to get a 60% solution?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How many liters of a 30% alcohol solution must be mixed with 60 liters of 90% solution to get a 60% solution?
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Equation:
alc + alc = alc
0.30x + 0.90(60) = 0.60(x+60)
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30x + 90*60 = 60x + 60*60
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-30x = -30*60
x = 60 liters (amt. of 30% solution needed)
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Cheers,
Stan H.
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