SOLUTION: how many pounds of tea that cost $4.20 per pound must be mixed with 12lb of tea that cost $2.25 per pound to make a mixture that cost $3.40 per pound?

Question 71527: how many pounds of tea that cost $4.20 per pound must be mixed with 12lb of tea that cost $2.25 per pound to make a mixture that cost $3.40 per pound?
Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Let x=number of pounds of $4.20 tea
Cost of $4.20 tea ($4.20x) plus cost of $2.25 tea ($2.25*12) must equal cost of final mixture (x+12)($3.40). So our equation to solve is:
$4.20x+$2.25*12=$3.40(x+12) get rid of parens and simplify
$4.20x+$27.00=$3.40x+$40.80 subtract $27.00 and also $3.40x from both sides
$4.20x+$27.00-$27.00-$3.40x=$3.40x-$3.40x+$40.80-$27.00 collect like terms
$.8x=$13.80 divide both sides by $.8
x=17.25 lb-------------------number of lbs of $4.20 tea
CK
$4.20(17.25)+$2.25(12)=$3.40(29.25)
$72.45+$27=$99.45
$99.45=$99.45
Hope this helps----ptaylor

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