SOLUTION: Rhonda and Yolanda are racing when Rhonda trips and falls, putting her 93 meters behind. She gets up and continues racing at her speed of 10.7 meters per second, while Yolanda cont

Question 713849: Rhonda and Yolanda are racing when Rhonda trips and falls, putting her 93 meters behind. She gets up and continues racing at her speed of 10.7 meters per second, while Yolanda continues at her speed of 10 meters per second. At this rate, how many seconds will it take for Rhonda to catch up to Yolanda? Give your answer to two decimal places.
Answer by ankor@dixie-net.com(22740) (Show Source): You can put this solution on YOUR website!
Rhonda and Yolanda are racing when Rhonda trips and falls, putting her 93 meters behind.
She gets up and continues racing at her speed of 10.7 meters per second, while Yolanda continues at her speed of 10 meters per second.
At this rate, how many seconds will it take for Rhonda to catch up to Yolanda?
Give your answer to two decimal places.
:
This would be the same as giving Y a 93 m head start
:
let t = time for R to catch Y
:
Write distance equation; dist = speed * time
:
10.7t = 10t + 93
10.7t - 10t = 93
.7t = 93
t = 93/.7
t = 132.86 seconds
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