SOLUTION: if a pharmacist has 20L of a 10% drug solution. How many liters of 5$ solution must be added to get a mixture that is 8%? I need help setting up the problem. I can get the answer i

Question 712971: if a pharmacist has 20L of a 10% drug solution. How many liters of 5$ solution must be added to get a mixture that is 8%? I need help setting up the problem. I can get the answer im just not sure how to set this up correctly.
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
if a pharmacist has 20L of a 10% drug solution. How many liters of 5$ solution must be added to get a mixture that is 8%?
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Equation:
drug + drug = drug
0.10*20 + 0.05x = 0.08(20+x)
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Multiply thru by 100 to get:
10*20 + 5x = 8*20 + 8x
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3x = 2*20
x = 40/3
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x = 13 1/3 L (amt. of 5% solution needed)
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Cheers,
Stan H.
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