SOLUTION: How many liters of pure water should be mixed with a 16-L solution of 90% acid to produce a mixture that is 90% water?
Algebra.Com
Question 712536: How many liters of pure water should be mixed with a 16-L solution of 90% acid to produce a mixture that is 90% water?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How many liters of pure water should be mixed with a 16-L solution of 90% acid to produce a mixture that is 90% water?
------------
Equation:
water + water = water
0.10*16 + 1*x = 0.90(16 + x)
Multiply thru by 100 to get:
10*16 + 100x = 90*16 + 90x
----
10x = 80*16
x = 8*16 = 128 liters (amt. of pure water needed)
=======
Cheers,
Stan H.
==================
RELATED QUESTIONS
how many liters of pure water should be mixed with a 13-L solution of 90% acid to produce (answered by josgarithmetic)
How many liters of pure water should be mixed with a 17-L solution of 90% acid to produce (answered by josgarithmetic)
How many liters of pure water should be mixed with a 13-L solution of 90% acid to produce (answered by Alan3354)
How many liters of pure water should be mixed with a 12-L solution of 70% acid to produce (answered by richwmiller)
How many liters of pure water should be mixed with a 9-L solution of 90% acid to produce... (answered by richwmiller)
how many liters of pure water should be mixed with a 3-L solution of 80% acid to produce... (answered by ankor@dixie-net.com)
How many liters of pure water should be mixed with an 8-L solution of 60% acid to produce (answered by stanbon,richwmiller)
How many liters of pure water should be mixed with a 12 liter solution of 90% acid to... (answered by josgarithmetic)
How many Liters of pure water should be mixed with a 17-L solution of 60% acid to produce (answered by stanbon)