SOLUTION: What quantity of a 60% acid solution must be mixed with a 35% solution to produce 600 mL of a 45% solution?

Question 712509: What quantity of a 60% acid solution must be mixed with a 35% solution to produce 600 mL of a 45% solution?

Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
Assign some variables to everyting.
M=600 ml. result solution
u= volume of 35% solution
v = volume of 60% solution
T = 45% solution wanted
L = 35%
H = 60%
You want to find u and v.

The concentration equation symbolically can begin as .
Also fact is u+v=M. Solve this simpler one for v, to have v=M-u; substitute this into the rational equation, solve for u, and you will have, after algebraic steps:
, substitute the given values to find value for u, and then go back to and get the value for v.

SUBSTITUTING VALUES TO GET u:
,....
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