SOLUTION: The radiator in a car is filled with a solution of 60% antifreeze and 40% water. The manufacturer of the antifreeze suggests that for summer driving, optimal cooling of the engine

Question 711788: The radiator in a car is filled with a solution of 60% antifreeze and 40% water. The manufacturer of the antifreeze suggests that for summer driving, optimal cooling of the engine is obtained with only 50% antifreeze. If the capacity of the radiator is 3.6 L, how much coolant should be drained and replaced with water to reduce the antifreeze concentration to the recommended level?

Found 2 solutions by lwsshak3, heyimback:
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
The radiator in a car is filled with a solution of 60% antifreeze and 40% water. The manufacturer of the antifreeze suggests that for summer driving, optimal cooling of the engine is obtained with only 50% antifreeze. If the capacity of the radiator is 3.6 L, how much coolant should be drained and replaced with water to reduce the antifreeze concentration to the recommended level?
**
let x=amt of coolant to be drained and replaced with water.
3.6-x=amt of original solution remaining in radiator.
..
60%(3.6-x)+0%x=50%*3.6
2.16-.6x=1.8
.6x=.36
x=0.6
amt of coolant to be drained and replaced with water=.6 L
Answer by heyimback(1) (Show Source): You can put this solution on YOUR website!

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