SOLUTION: I don't understand how to create an algebraic formula to answer this question:
A solution of 75% vinegar is to be mixed with a solution of 22% vinegar to form 636 liters of a 70%
Algebra.Com
Question 710420: I don't understand how to create an algebraic formula to answer this question:
A solution of 75% vinegar is to be mixed with a solution of 22% vinegar to form 636 liters of a 70% solution. How many liters of the 75% solution must be used?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
A solution of 75% vinegar is to be mixed with a solution of 22% vinegar to form 636 liters of a 70% solution. How many liters of the 75% solution must be used?
------
Equation:
vinegar + vinegar = vinegar
-----
0.75x + 0.22(636-x) = 0.70*636
-----
Multiply thru by 100 to get:
75x + 22*636 - 22x = 70*636
-----
53x = 48*636
x = 576 liters (amt. of 75% solution needed)
----
636-x = 60 liters (amt. of 22% solution needed)
====================================================
Cheers,
Stan H.
==================
RELATED QUESTIONS
How many quarts of water should be mixed with a 30% vinegar solution to obtain 12 qt of a (answered by josmiceli)
I need help with this problem. A previous tutor replied with vinegar + vinegar=Vinegar.... (answered by stanbon)
please help with this question - it is from a review page my teacher made up.
White... (answered by Mathtut,Alan3354)
how much pure (100%) vinegar and 5% vinegar must be mixed to obtain 50oz of a 24%... (answered by oberobic)
Quick question.
23-(x-7)
Trying to understand how this is solved.
I know the... (answered by josgarithmetic)
Household cleaners: as a cleaning agent a solution that had is 28% vinegar is often used. (answered by Boreal)
A solution of 49% vinegar is to be mixed with a solution of 32% vinegar to form 153... (answered by nerdybill)
a solution of 63% vinegar is to be mixed with a solution of 28% vinegar to form 70 liters (answered by stanbon)
Pablo has 5 less than thrice the number of hats Juan has. If Pablo has 25 hats, how many... (answered by ikleyn)