SOLUTION: a scientist wants to make a solution that is 30% acid using one solution that is 50 % acid and another solution that is 20% acid.How many liters of each solution does the scientis
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Question 708706: a scientist wants to make a solution that is 30% acid using one solution that is 50 % acid and another solution that is 20% acid.How many liters of each solution does the scientist need to make 75 liters of the mixture?
Answer by josgarithmetic(39617) (Show Source): You can put this solution on YOUR website!
= known resulting volume, 75 liters
= low concentration material, 20%
= high concentration material, 50%
= the target concentration of mixture, 30%
= how much low concentration material to use
= how much high concentration material to use
INITIAL SYSTEM
Work with and possibly do other simplifications to the percent-concentration equation,
Use the volume sum equation to solve for either variable and substitute into the percentage equation and find the single variable there. As general example, solve for y:
x+y=v, . Substitute.
, and solve for x
Equivalent to multiplying both sides by -1
And that would be the symbolic form for x, the lower concentration material. Just substitute the given values.
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