SOLUTION: how many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 30% antifreeze to get a mixture that is 50% antifreeze?
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Question 707180: how many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 30% antifreeze to get a mixture that is 50% antifreeze?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how many gallons of a 60% antifreeze solution must be mixed with 90 gallons of 30% antifreeze to get a mixture that is 50% antifreeze?
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Equation:
anti + anti = anti
0.30*90 + 0.60x = 0.50(90+x)
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Multiply thru by 100 to get:
30*90 + 60x = 50*90 + 50x
10x = 20*90
x = 180 gallons (amt. of 60% mix to add)
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Cheers,
Stan H.
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