SOLUTION: Ten gallons of a 25% salt solution are to be obtained by mixing solutions that are 13% salt and 33% salt respectively. How many gallons of each are needed?

Question 70706: Ten gallons of a 25% salt solution are to be obtained by mixing solutions that are 13% salt and 33% salt respectively. How many gallons of each are needed?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
Ten gallons of a 25% salt solution are to be obtained by mixing solutions that are 13% salt and 33% salt respectively. How many gallons of each are needed?
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Let amount of 13% solution be "x" ; Amt of salt is 0.13x gals.
Amt of 33% solution is "10-x" gallons: Amt of salt is 0.33(10-x)=3.3-0.33x gals
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Amt of 25% solution is 10 gals ; Amt of salt is 0.25*10 = 2.5 gals
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EQUATION:
salt + salt = salt
0.13x +3.3-0.33x =2.5
-0.20x=-0.8
x= 4 gallons (amt of 13% solution to be mixed)
10-x= 6 gallons (amt of 33% solution to be mixed)
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Cheers,
Stan H.

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