SOLUTION: Mixing a 10% solution with a 18% solution to produce 5 pounds of a 12% solution. How many pounds of the 10% solution are required?

Question 703666: Mixing a 10% solution with a 18% solution to produce 5 pounds of a 12% solution. How many pounds of the 10% solution are required?
Found 2 solutions by nshah11, josmiceli:
Answer by nshah11(47) (Show Source): You can put this solution on YOUR website!
Assume x lbs of 10% solution is mixed with (5 - x) lbs of 18% solution.
(0.1x + 0.18(5 -x))/5 = 0.12
-0.08x + 0.9 = 0.6
x = 3.75 lbs
Answer by josmiceli(19441) (Show Source): You can put this solution on YOUR website!
Let = pounds of 10% solution needed
Let = pounds of 18% solution needed
--------------
given:
(1)
(2)
---------------------------
(2)
(2)
(2)
Multiply both sides of (1) by and
subtract (1) from (2)
(2)
(1)

and
(1)
(1)
3.75 pounds of 10% solution are needed
1.25 pounds of 18% solution are needed
check:
(2)
(2)
(2)
(2)
(2)
OK

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