SOLUTION: How many liters of 80% alcohol solution and 20% alcohol solution must be mixed to obtain 15 liters of 60% alcohol solution?
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Question 692446: How many liters of 80% alcohol solution and 20% alcohol solution must be mixed to obtain 15 liters of 60% alcohol solution?
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
.80X+.20(15-X)=15*.60
.80X+3-.20X=9
.60X=9-3
.60X=6
X=6/.60
X=10 LITERS OF 80% SOLUTION IS USED.
15-10=5 LITERS OF 20% SOLUTION IS USED.
PROOF:
.80*10+.20*5=9
8+1=9
9=9
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