SOLUTION: Here is my problem as written in my homework: A metallurgist needs to produce 10kg of an alloy which is 65% copper and 35% tin. He has an alloy which is 50% copper and 50% tin. Ho

Question 682079: Here is my problem as written in my homework:
A metallurgist needs to produce 10kg of an alloy which is 65% copper and 35% tin. He has an alloy which is 50% copper and 50% tin. How much of this 50-50 alloy must he melt together with pure copper to make the desired alloy? How much pure copper must he use?
Here is how I attempted to solve the problem:
(10-x)(.50)(.50)+(x)(1)=10(.65)(.35)
So the answer that I got was that he would need 2.03 kg of the pure copper and 7.97 kilograms of the 50-50 mixture.
When I substituted the numbers into my equation, it did not come out right.
Thank you for your time and patience.
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
Here is my problem as written in my homework:
A metallurgist needs to produce 10kg of an alloy which is 65% copper and 35% tin. He has an alloy which is 50% copper and 50% tin. How much of this 50-50 alloy must he melt together with pure copper to make the desired alloy? How much pure copper must he use?
**
let x=amt of pure copper to be melted with 50-50 alloy
10-x=amt of 50-50 alloy to be melted with pure copper
..
100%*x+50%*(10-x)=65%*10
x+(10-x)/2=6.5
2x+10-x=2*6.5=13
x+10=13
x=3
10-x=7
amt of pure copper to be melted with 50-50 alloy=3kg
amt of 50-50 alloy to be melted with pure copper=7kg
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