SOLUTION: how many liters of a 40% alcohol solution must be mixed 60 liters of a 70% solution to get a 50% solution

Question 680439: how many liters of a 40% alcohol solution must be mixed 60 liters of a 70% solution to get a 50% solution
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
how many liters of a 40% alcohol solution must be mixed 60 liters of a 70% solution to get a 50% solution
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Using 2 equation:
Quantity Eq:: x + 60 = y
Alcohol Eq:::0.40x + 0.70*60 = 0.50y
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Multiply thru Quantity Eq by 40
Multiply thru Alcohol Eq by 100
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40x + 40*60 = 40y
40x + 70*60 = 50y
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Subtract and solve for "y":
30*60 = 10y
y = 180 liters
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Solve for "x":
x + 60 = y
x + 60 = 180
x = 120 liters (amt. of 40% solution needed)
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Cheers,
Stan H.
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