SOLUTION: A dealer has tea worth $1.20 a pound and tea worth $1.90 a pound. How many pounds of each kind must he use to make 70 pounds that can be sold for 1.50 per pound?

Algebra.Com
Question 676582: A dealer has tea worth $1.20 a pound and tea worth $1.90 a pound. How many pounds of each kind must he use to make 70 pounds that can be sold for 1.50 per pound?
Answer by ewatrrr(24785)   (Show Source): You can put this solution on YOUR website!
 
Hi
How many pounds of each kind must he use to make 70 pounds that can be sold for 1.50 per pound?
has tea worth $1.20 a pound and tea worth $1.90 a pound.
Mixing algebraically
1.90x + 1.20(70-x) = 1.50 • 70
.70x = .30• 70
x = 30lb of the $1.90 and 40lb of the $1.20
and

RELATED QUESTIONS

A dealer has tea worth $1.20 a pound and tea worth $1.90 a pound. How many pounds of each (answered by Paul)
a seedman has seeds worth $.70 per pound and seeds worth $.90 per pound. How many pounds... (answered by checkley77)
A grocer wishes to mix $1.20 tea with $1.50 tea to make a mixture of 60 pounds worth... (answered by richwmiller)
A grocer has two kinds of tea: one selling for 80 cents a pound and the other selling for (answered by stanbon)
Using the 5 step process solve showing the work for: A dealer has some hard candy worth... (answered by josgarithmetic)
A store manager mixes candy worth 90 cents per pound with gumdrops worth $1.50 per pound... (answered by scott8148)
A store manager mixes candy worth 90 cent per pound with gumdrops worth $1.50 per pound... (answered by Alan3354,ewatrrr)
A grocer has two kinds of tea, one selling for 80 cents per pound and the other selling... (answered by josgarithmetic)
A grocer has two kinds of loose tea. One is worth $5 per pound and the other is worth $7... (answered by josmiceli)