SOLUTION: how many liters of a 60% acid solution must be mixed with a 10% acid solution to get 400 L of a 50% acid solution
Algebra.Com
Question 674714: how many liters of a 60% acid solution must be mixed with a 10% acid solution to get 400 L of a 50% acid solution
Answer by checkley79(3341) (Show Source): You can put this solution on YOUR website!
.60X+.10(400-X)=.50*400
.60X+40-.10X=200
.50X=200-40
.50X=160
X=160/.50
X=320L OF 60% ACID IS USED.
400-320=80L OF 10% ACID IS USED.
PROOF:
.60*320+.10*80=200
192+8=200
200=200
RELATED QUESTIONS
how many liters of a 60% acid solution must be mixed with a 15% acid solution to get 405... (answered by ankor@dixie-net.com)
How many liters of 60% acid solution must be mixed with a 30% acid solution to get 240 L... (answered by ewatrrr)
how many liters of a 60 acid solution must be mixed with 15% acid solution to get 360 l... (answered by josgarithmetic)
How many liters of a 50% acid solution must be mixed with a 10% acid solution to get 360... (answered by mananth)
How many liters of 70% acid solution must be mixed with 10% acid solution to get 480 L of (answered by stanbon)
how many liters of a 70% acid solution must be mixed with a 30% acid solution to get 400... (answered by josgarithmetic)
How many liters of a 70% acid solution must be mixed with a 25% acid solution to get 270... (answered by Fombitz)
how many liters of a 70% acid solution must be mixed with a 30% acid solution to get 240... (answered by macston)
How many liters of a 70% acid solution must be mixed with a 25% acid solution to get 315... (answered by josgarithmetic)