SOLUTION: How many gallons of a 40 percent solution must be mixed with 60 gallons of a 22 percent solution to obtain a solution that is 30 percent alcohol?

Question 674056: How many gallons of a 40 percent solution must be mixed with 60 gallons of a 22 percent solution to obtain a solution that is 30 percent alcohol?
Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
How many gallons of a 40 percent solution must be mixed with 60 gallons of a 22 percent solution to obtain a solution that is 30 percent alcohol?
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Quantity Equation: x + 60 = y
Percent Equation: 0.40x+0.22*60 = 0.30*y
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Multiply thru 1st by 40
Multiply thru 2nd by 100
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40x + 40*60 = 40*y
40x + 22*60 = 30*y
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Subtract and solve for "y"
18*60 = 10y
y = 108 gallons
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Solve for "x":
x + 60 = y
x = 108-60
x = 48 gallons (amt. of 40% solution needed)
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Cheers,
Stan H.
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