# SOLUTION: A jeweler is using 10 lbs. of an alloy that is 2% robium. He has another alloy which is 5% robium. He wishes to combine these mixtures to form a mixture that is 3% robium. How m

Algebra ->  Algebra  -> Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A jeweler is using 10 lbs. of an alloy that is 2% robium. He has another alloy which is 5% robium. He wishes to combine these mixtures to form a mixture that is 3% robium. How m      Log On

 Ad: Over 600 Algebra Word Problems at edhelper.com Ad: Algebrator™ solves your algebra problems and provides step-by-step explanations! Ad: Algebra Solved!™: algebra software solves algebra homework problems with step-by-step help!

 Word Problems: Mixtures Solvers Lessons Answers archive Quiz In Depth

 Click here to see ALL problems on Mixture Word Problems Question 66582: A jeweler is using 10 lbs. of an alloy that is 2% robium. He has another alloy which is 5% robium. He wishes to combine these mixtures to form a mixture that is 3% robium. How many pounds of the second alloy should be added to the first to get a mixture that is 3% robium. I really need help, so I would ask for step by step instructions please. Thank you. Answer by stanbon(57967)   (Show Source): You can put this solution on YOUR website!A jeweler is using 10 lbs. of an alloy that is 2% robium. He has another alloy which is 5% robium. He wishes to combine these mixtures to form a mixture that is 3% robium. How many pounds of the second alloy should be added to the first to get a mixture that is 3% robium. ------------------- 2% alloy DATA: Amount = 10 lbs ; amount of robium= 0.02(10)=0.2 lbs -------------- 5% alloy DATA: Amount= x lbs ; amount of robium=0.05x lbs. ------------ Mixture DATA: Amount = x+10 lbs ; amount of robium = 0.3(x+10)=(0.03x+0.3) lbs ---------------- EQUATION: robium + robium = robium 0.2 +0.05x = 0.03x+0.3 0.02x=0.1 x=5 lbs (amount of 5% alloy that must be added) Cheers, Stan H.