SOLUTION: a lab technician has one solution that is 60% chlorinated and another that is 40% chlorinated. how much of each solution is needed to make a 100 L solution that is 50% clorine?

Question 66574This question is from textbook
: a lab technician has one solution that is 60% chlorinated and another that is 40% chlorinated. how much of each solution is needed to make a 100 L solution that is 50% clorine? This question is from textbook

Answer by stanbon(75887) (Show Source): You can put this solution on YOUR website!
a lab technician has one solution that is 60% chlorinated and another that is 40% chlorinated. how much of each solution is needed to make a 100 L solution that is 50% clorine?
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60% solution DATA:
Amount is "x" L ; amount of chlorine in them is 0.6x L
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40% solution DATA:
Amount is "100-x" L ; amount of chlorine in them is 0.4(100-x)=(40-0.4x) L
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Mixture DATA:
Amount is 100 L ; amount of chlorine is 0.5(100)= 50 L
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EQUATION:
chlorine + chlorine = chlorine
0.6x + 40-0.4x = 50
0.3x=10
x=33.3 L (amount of 60% solution in the mixture)
100-33.3 L = 66.7 L (amount of 40% solution in the mixture)
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Cheers,
Stan H.
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