SOLUTION: pure acid is to be added to a 10%acid solution to obtain 90l of 89% solution . what amounts of each should be used?

Question 665032: pure acid is to be added to a 10%acid solution to obtain 90l of 89% solution . what amounts of each should be used?
Answer by vleith(2983) (Show Source): You can put this solution on YOUR website!
Let the amount of pure acid be given by x. Then if the total volume is 90 liters, the amount of 10% acid is given by (90-x). Plug that in and solve
100%x + 10%(90-x) = 89%(90)

so there must be 11 liters of 10% to start with.
And remember .... add acid to water, just like you oughta (and not the other way around)
RELATED QUESTIONS
pure acid is to be added to a 10% acid solution to obtain 90L of 44% solution what... (answered by josgarithmetic)

pure acid is to be added to a 10%acid solution to obtain 90l of 22% solution . what... (answered by josmiceli)

pure acid is to be added to a 10% acid solution to obtain 90L of 42% solution what... (answered by addingup)

pure acid is to be added to a 10% acid solution to obtain 90l of 75% solution? what... (answered by Fombitz,ewatrrr,josmiceli)

pure acid is to be added to a 10% acid solution to obtain 90L of 32% soulution. what... (answered by ikleyn,greenestamps)

Pure acid is to be added to a 10% acid solution to obtain 90l of 56% solution. What... (answered by stanbon)

pure acid is to be added to a 10% acid solution to obtain 90L of 19% solution. what... (answered by jorel1380)

Pure acid is to be added to a 10% solution to obtqin 90L of 14% solution. What amounts of (answered by josgarithmetic)

pure acid is to be added to 10% acid solution to obtain 90L of 53% solution. what amount... (answered by stanbon)