# SOLUTION: A jar filled with change is holding \$5.45 and has 41 coins. There are nickels, dimes and quarters. If we remove the nickels, the remaining coins have a value of \$4.55. How many

Algebra ->  Customizable Word Problem Solvers  -> Mixtures -> SOLUTION: A jar filled with change is holding \$5.45 and has 41 coins. There are nickels, dimes and quarters. If we remove the nickels, the remaining coins have a value of \$4.55. How many       Log On

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 Click here to see ALL problems on Mixture Word Problems Question 664309: A jar filled with change is holding \$5.45 and has 41 coins. There are nickels, dimes and quarters. If we remove the nickels, the remaining coins have a value of \$4.55. How many of each type of coin was there originally? Set up a system of 3 equations and solve to answer this question. Show your work!Answer by lynnlo(4174)   (Show Source): You can put this solution on YOUR website!18 nickels=========.90 15 quarters========\$3.75 8 dimes============.80 you have a total of ==41 coins== take the nickels out from the total of \$5.45,you have \$4.55