Hi,

Pure acid is to be added to a 5% acid solution to obtain 95L of 28% solution.

Algebraically Question states***  acid = acid

 

                

                      x = 23L, amount of pure acid to add to 72L of the 5% solution

and...

  = 26.6L of acid are involved



Donations on my website are appreciated.  Thanks.  ewatrrr

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