SOLUTION: there are 12 liters of 60% acid solution. How much must be drained and replaced with pure acid to get a final strength of 75%?
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Question 661483: there are 12 liters of 60% acid solution. How much must be drained and replaced with pure acid to get a final strength of 75%?
Answer by lwsshak3(11628) (Show Source): You can put this solution on YOUR website!
there are 12 liters of 60% acid solution. How much must be drained and replaced with pure acid to get a final strength of 75%?
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let x=amt of 60% acid solution to be drained and replaced with pure acid.
12-x=amt of 60% acid solution remaining in container
..
60%(12-x)+100%x=75%*12
7.2-.6x+x=9
.4x=1.8
x=4.5
amt of 60% acid solution to be drained and replaced with pure acid=4.5 liters
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