SOLUTION: Determine how much pure water would have to be mixed with 60ml of 80% sulfuric acid to create a 50% solution of sulfuric acid solution?

Question 658991: Determine how much pure water would have to be mixed with 60ml of 80% sulfuric acid to create a 50% solution of sulfuric acid solution?
Answer by Alan3354(69443) (Show Source): You can put this solution on YOUR website!
Determine how much pure water would have to be mixed with 60ml of 80% sulfuric acid to create a 50% solution of sulfuric acid solution?
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60*0.8 = 48 ml of acid.
To be 50%, 48 ml of water are needed --> 96 ml of solution.
96 - 60 = 36 ml of water to add.
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Or,
x*0 + 60*80 = (60 + x)*50
3000 + 50x = 4800
50x = 1800
x = 36 ml
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