SOLUTION: Exactly how many liters of pure alcohol must be added to 50 liters of a 25% alcohol solution to obtain a 45% solution?

Question 65511This question is from textbook Essential Algebra
: Exactly how many liters of pure alcohol must be added to 50 liters of a 25% alcohol solution to obtain a 45% solution?This question is from textbook Essential Algebra

Found 3 solutions by uma, checkley71, josmiceli:
Answer by uma(370)   (Show Source):
You can put this solution on YOUR website!
Let x ltrs of pure alcohol solution be added to 50 ltrs of a 25% alcohol solution to obtain a 45% solution.
==> the equation would be:
x*1 + 50*(0.25) = (50+x)*(0.45)
==> x + 12.5 = 22.5 + o.45 x
==> x - 0.45x = 22.5 - 12.5
==> 0.55x = 10
==> 0.55x/0.55 = 10/0.55
==> x = 18.18
Thus 18.18 ltrs of pure alcohol solution be added to 50 ltrs of a 25% alcohol solution to obtain a 45% solution.
Good Luck!!!

Answer by checkley71(8403)   (Show Source):
You can put this solution on YOUR website!
50*.25+x=(50+x).45
12.5+x=22.5+.45x
x-.45x=22.5-12.5
.55x=10
x=10/.55
x=18.182
proof
50*.25+18.182=(50+18.182).45
12.5+18.182=68.182*.45
30.682=30.682
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MERRY CHRISTMAS

Answer by josmiceli(9674)   (Show Source):
You can put this solution on YOUR website!
x = liters of alcohol to be added to the 50 liters mixture
= liters of alcohol already in the mixture

Answer: add 10 liters of alcohol to the 50 liters of 25% mixture
to get a 45% mixture
check

OK