SOLUTION: A druggist needs 25 liters of a solution that is 16% iodine. She has one solution that is 12% iodine and another solution that is 37% iodine. How many liters of each solution shoul

Question 64839This question is from textbook An Incremental Development
: A druggist needs 25 liters of a solution that is 16% iodine. She has one solution that is 12% iodine and another solution that is 37% iodine. How many liters of each solution should the druggiest use? This question is from textbook An Incremental Development

Answer by ptaylor(2198) (Show Source): You can put this solution on YOUR website!
Let x=number of liters of 37% iodine
Then 25-x=number of liters of 12% iodine
Now we know that the amount of pure iodine in the 37% solution (.37)(x) plus the amount of pure iodine in the 12% solution .12(25-x) must equal the amount of pure iodine in the final solution (25)(.16) so our equation to solve:
.37x+.12(25-x)=25(.16) simplifying we get:
.37x-.12x+3=4 collecting like terms we have:
.25x=4-3 or
.25x=1
x=4 liters of the 37% solution
25-x=25-4=21 liters of 12% solution
ck
.37(4)+.12(25-4)=25(.16)
1.48+2.52=4
4=4
Hope this helps. Happy holidays.-----ptaylor
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