SOLUTION: A car radiator contains 10 liters of a 30% antifreeze solution. How many liters will have to be replaced with pure antifreeze if the resulting solution is to be 50% antifreeze?

Question 648067: A car radiator contains 10 liters of a 30% antifreeze solution. How many liters will have to be replaced with pure antifreeze if the resulting solution is to be 50% antifreeze?
Answer by nerdybill(7384) (Show Source): You can put this solution on YOUR website!
A car radiator contains 10 liters of a 30% antifreeze solution. How many liters will have to be replaced with pure antifreeze if the resulting solution is to be 50% antifreeze?
.
Let x = amount (liters) replaced with pure antifreeze
then
.30(10-x) + x = .50(10)
3-.30x + x = 5
3+.70x = 5
.70x = 2
x = 2/.70
x = 20/7 liters
or, approximately
x = 2.86 liters

RELATED QUESTIONS
a car radiator containes 10 liters of a 30% antifreeze solution. how many liters will... (answered by stanbon)

A car radiator contains 10 liters of a 20 percent antifreeze solution. How many liters... (answered by stanbon)

Can you help me answer this: A car radiator contains 10 liters of 30% solution. How many (answered by chessace)

a car radiator contains 10 liters of a 30 percent anti freeze solution how many liters... (answered by ankor@dixie-net.com)

Please help me with this mixture problem. I have no idea how to do it. THanks A car... (answered by Earlsdon)

A car radiator contains 5 liters of a 25% antifreeze solution. How many liters must be... (answered by nerdybill)

A radiator contains 6 liters of a 25% antifreeze solution. How much should be drained... (answered by checkley75)

A radiator contains 6 liters of a 25% antifreeze solution. How much should be drained and (answered by josgarithmetic)

a radiator contains 6 liters of a 33% antifreeze solution. how much water should be... (answered by richwmiller)