SOLUTION: How many gallons of 20% alcohol solution must be mixed with 10 gallons of a 50% alcohol solution to obtain a 30% alcohol solution?
Algebra.Com
Question 645445: How many gallons of 20% alcohol solution must be mixed with 10 gallons of a 50% alcohol solution to obtain a 30% alcohol solution?
Answer by sachi(548) (Show Source): You can put this solution on YOUR website!
let x gl of 20% alcohol solution must be mixed with 10 gallons of a 50% alcohol solution to obtain a 30% alcohol solution
so 20x/100+10*50/100=(x+10)*30/100
or 20x+500=30(x+10)=30x+300
or 10x=200
or x=20 gallons
ans
RELATED QUESTIONS
How many gallons of a 25% alcohol solution must be mixed with 20 gallons of a 50% alcohol (answered by josmiceli)
"How many gallons of a 25% alcohol solution must be mixed with 10 gallons of a 50%... (answered by Alan3354)
How many gallons of 30% alcohol must be mixed with 60 gallons of 14% alcohol to obtain a (answered by Mathtut)
How many gallons of 30% alcohol must be mixed with 60 gallons of 14% alcohol to obtain a... (answered by louiramirez229@yahoo.com,josmiceli)
How many gallons of a 50% alcohol solution must be mixed with 30 gallons of an 18%... (answered by ewatrrr)
How many gallons of a 70% alcohol solution must be mixed with 50 gallons of a 20%... (answered by stanbon)
How many gallons of a 30% alcohol solution must be mixed with 60 gallons of a 14%... (answered by josgarithmetic)
How much of a 40% alcohol solution must be mixed with 50 gallons of an 18% alcohol... (answered by richwmiller)
How many gallons of a 30% alcohol solution must be mixed with a 60gallons of 14% solution (answered by richwmiller)